4y^2+28y+13=

Solution for 4y^2+28y+13= equation:

Simplifying
4y2 + 28y + 13 = 0

Reorder the terms:
13 + 28y + 4y2 = 0

Solving
13 + 28y + 4y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(13 + 2y)(1 + 2y) = 0

Subproblem 1
Set the factor '(13 + 2y)' equal to zero and attempt to solve:

Simplifying
13 + 2y = 0

Solving
13 + 2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 2y = 0 + -13

Combine like terms: 13 + -13 = 0
0 + 2y = 0 + -13
2y = 0 + -13

Combine like terms: 0 + -13 = -13
2y = -13

Divide each side by '2'.
y = -6.5

Simplifying
y = -6.5
Subproblem 2
Set the factor '(1 + 2y)' equal to zero and attempt to solve:

Simplifying
1 + 2y = 0

Solving
1 + 2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2y = 0 + -1
2y = 0 + -1

Combine like terms: 0 + -1 = -1
2y = -1

Divide each side by '2'.
y = -0.5

Simplifying
y = -0.5
Solution
y = {-6.5, -0.5}